JuniorTheoryCommon

What does the program print?

SWIFT

var count = 0
outer: for _ in 1...3 {
    for j in 1...3 {
        if j == 3 {
            break outer
        }
        count += 1
    }
}
print(count)

Expecting 6: thinking break always ends only the innermost loop. With a label, break outer ends the outer loop too, so there is no second outer pass.
Expecting 3: thinking break lets the current pass finish. It acts at once, so count += 1 below it does not run when j is 3.

What does the program print if break outer is replaced with a plain break?
What would continue outer do in the same place?

Back to questions Open topic in roadmap →Answer it yourself — Quiz

Back to questions

JuniorTheoryCommon

What does the program print?

SWIFT

var count = 0
outer: for _ in 1...3 {
    for j in 1...3 {
        if j == 3 {
            break outer
        }
        count += 1
    }
}
print(count)

Expecting 6: thinking break always ends only the innermost loop. With a label, break outer ends the outer loop too, so there is no second outer pass.
Expecting 3: thinking break lets the current pass finish. It acts at once, so count += 1 below it does not run when j is 3.

What does the program print if break outer is replaced with a plain break?
What would continue outer do in the same place?

Back to questions Open topic in roadmap →Answer it yourself — Quiz