JuniorTheoryCommon

What does the program print?

Python

def make_counter():
    count = 0

    def counter():
        nonlocal count
        count += 1
        return count
    return counter


c = make_counter()
print(c(), c(), make_counter()())

1 2 1

Expecting 3 from make_counter()(): each call of make_counter creates a new count starting at 0, so the new counter returns 1.
Expecting count to restart on every c() call: count = 0 runs only in make_counter, and nonlocal makes counter update that one variable.

What happens if you remove the nonlocal count line?
How would you make two counters that start at different numbers?

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JuniorTheoryCommon

What does the program print?

Python

def make_counter():
    count = 0

    def counter():
        nonlocal count
        count += 1
        return count
    return counter


c = make_counter()
print(c(), c(), make_counter()())

1 2 1

Expecting 3 from make_counter()(): each call of make_counter creates a new count starting at 0, so the new counter returns 1.
Expecting count to restart on every c() call: count = 0 runs only in make_counter, and nonlocal makes counter update that one variable.

What happens if you remove the nonlocal count line?
How would you make two counters that start at different numbers?

Back to questions Open topic in roadmap →Answer it yourself — Quiz