JuniorTheoryCommon

What does the program print?

Python

def check(x):
    try:
        y = 10 / x
    except ZeroDivisionError:
        return "zero"
    else:
        return "ok"
    finally:
        print("done", end=" ")


print(check(0))

done zero

Expecting zero, as if return left the function at once: finally runs on the way out of try, even past a return, so done is printed first.
Expecting zero done: finally runs inside check, before the function hands back "zero", so the outer print gets the value only after done is out.

What does print(check(5)) print?
Why does print("done", end=" ") keep both words on one line?

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JuniorTheoryCommon

What does the program print?

Python

def check(x):
    try:
        y = 10 / x
    except ZeroDivisionError:
        return "zero"
    else:
        return "ok"
    finally:
        print("done", end=" ")


print(check(0))

done zero

Expecting zero, as if return left the function at once: finally runs on the way out of try, even past a return, so done is printed first.
Expecting zero done: finally runs inside check, before the function hands back "zero", so the outer print gets the value only after done is out.

What does print(check(5)) print?
Why does print("done", end=" ") keep both words on one line?

Back to questions Open topic in roadmap →Answer it yourself — Quiz