JuniorTheoryCommon

What does the program print?

PHP

<?php

function price($amount, $discount = 0, $tax = 20)
{
    return $amount - $discount + $tax;
}

echo price(100, tax: 0), ' ', price(100, 5), "\n";

100 115

Expecting an error for the skipped $discount: a parameter with a default may be left out, and the named argument after it sets $tax directly.
Expecting the 5 in price(100, 5) to reach $tax: positional arguments fill parameters left to right, so 5 is $discount and the call is 100 - 5 + 20.

What happens if you call price(tax: 0) without the first argument?
Why does PHP refuse price(tax: 0, 100) before the program runs?

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JuniorTheoryCommon

What does the program print?

PHP

<?php

function price($amount, $discount = 0, $tax = 20)
{
    return $amount - $discount + $tax;
}

echo price(100, tax: 0), ' ', price(100, 5), "\n";

100 115

Expecting an error for the skipped $discount: a parameter with a default may be left out, and the named argument after it sets $tax directly.
Expecting the 5 in price(100, 5) to reach $tax: positional arguments fill parameters left to right, so 5 is $discount and the call is 100 - 5 + 20.

What happens if you call price(tax: 0) without the first argument?
Why does PHP refuse price(tax: 0, 100) before the program runs?

Back to questions Open topic in roadmap →Answer it yourself — Quiz