JuniorTheoryCommon

What happens when the program runs?

JavaScript

const x = 1;
console.log(x);
x = 2;
console.log(x);

1, then TypeError

Expecting 1, then 2: a const cannot get a new value. The line x = 2 stops the program with TypeError: Assignment to constant variable.; use let for a variable that changes.
Expecting only TypeError: the assignment fails only when its line runs. Line 2 has already printed 1 by then.

JuniorTheoryCommon

JavaScript

const x = 1;
console.log(x);
x = 2;
console.log(x);

1, then TypeError

Expecting 1, then 2: a const cannot get a new value. The line x = 2 stops the program with TypeError: Assignment to constant variable.; use let for a variable that changes.
Expecting only TypeError: the assignment fails only when its line runs. Line 2 has already printed 1 by then.