JuniorTheoryCommon

What does the program print?

JAVA

public class Main {
    public static void main(String[] args) {
        String a = "hi";
        String b = new String("hi");
        System.out.println((a == b) + " " + a.equals(b));
    }
}

false true

Expecting true true: the literal "hi" sits in the string pool, but new String builds a separate object, so == on the two references is false.
Expecting false false: String.equals compares characters, not references, so two objects with the same text are equal.

What does a == b give when both variables hold the literal "hi"?
How do you compare two strings while ignoring letter case?

Back to questions Open topic in roadmap →Answer it yourself — Quiz

Back to questions

JuniorTheoryCommon

What does the program print?

JAVA

public class Main {
    public static void main(String[] args) {
        String a = "hi";
        String b = new String("hi");
        System.out.println((a == b) + " " + a.equals(b));
    }
}

false true

Expecting true true: the literal "hi" sits in the string pool, but new String builds a separate object, so == on the two references is false.
Expecting false false: String.equals compares characters, not references, so two objects with the same text are equal.

What does a == b give when both variables hold the literal "hi"?
How do you compare two strings while ignoring letter case?

Back to questions Open topic in roadmap →Answer it yourself — Quiz