JuniorTheoryCommon

What does the program print?

JAVA

public class Main {
    public static void main(String[] args) {
        int x = Integer.MAX_VALUE;
        x++;
        System.out.println(x);
    }
}

-2147483648

Expecting 2147483648: x is an int whose maximum is 2147483647, and x++ keeps the type, so the value wraps to -2147483648.
Expecting an error or an exception: Java does not check int arithmetic for overflow; only methods such as Math.addExact throw.

How would you add one to Integer.MAX_VALUE and get 2147483648?
What does Math.addExact(Integer.MAX_VALUE, 1) do?

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Back to questions

JuniorTheoryCommon

What does the program print?

JAVA

public class Main {
    public static void main(String[] args) {
        int x = Integer.MAX_VALUE;
        x++;
        System.out.println(x);
    }
}

-2147483648

Expecting 2147483648: x is an int whose maximum is 2147483647, and x++ keeps the type, so the value wraps to -2147483648.
Expecting an error or an exception: Java does not check int arithmetic for overflow; only methods such as Math.addExact throw.

How would you add one to Integer.MAX_VALUE and get 2147483648?
What does Math.addExact(Integer.MAX_VALUE, 1) do?

Back to questions Open topic in roadmap →Answer it yourself — Quiz