JuniorTheoryCommon

What happens when the program is compiled and run?

JAVA

public class Main {
    static int sign(int x) {
        if (x > 0) {
            return 1;
        } else if (x < 0) {
            return -1;
        }
    }
    public static void main(String[] args) {
        System.out.println(sign(5));
    }
}

It does not compile

Expecting 1: the compiler does not look at the call sign(5); it checks that every path through sign returns a value, and x == 0 reaches the end with none.
Expecting 0 or a run-time error: a method gets no default result; a path without return stops the build with missing return statement.

How would you change sign so that it compiles and returns 0 for zero?
Why does a void method compile without any return?

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Back to questions

JuniorTheoryCommon

What happens when the program is compiled and run?

JAVA

public class Main {
    static int sign(int x) {
        if (x > 0) {
            return 1;
        } else if (x < 0) {
            return -1;
        }
    }
    public static void main(String[] args) {
        System.out.println(sign(5));
    }
}

It does not compile

Expecting 1: the compiler does not look at the call sign(5); it checks that every path through sign returns a value, and x == 0 reaches the end with none.
Expecting 0 or a run-time error: a method gets no default result; a path without return stops the build with missing return statement.

How would you change sign so that it compiles and returns 0 for zero?
Why does a void method compile without any return?

Back to questions Open topic in roadmap →Answer it yourself — Quiz