JuniorTheoryCommon

What happens when the program is compiled and run?

JAVA

public class Main {
    public static void main(String[] args) {
        int n = 3;
        String s = switch (n) {
            case 1 -> "one";
            case 2 -> "two";
        };
        System.out.println(s);
    }
}

It does not compile

Expecting null or a blank line: a switch expression must cover every possible value of n, and without default the compiler rejects it.
Expecting a run-time error: the compiler checks coverage before the program runs, whatever value n holds.

How does yield hand a value out of a block branch of a switch expression?
Why does a switch expression over an enum need no default when it lists every constant?

Back to questions Open topic in roadmap →Answer it yourself — Quiz

Back to questions

JuniorTheoryCommon

What happens when the program is compiled and run?

JAVA

public class Main {
    public static void main(String[] args) {
        int n = 3;
        String s = switch (n) {
            case 1 -> "one";
            case 2 -> "two";
        };
        System.out.println(s);
    }
}

It does not compile

Expecting null or a blank line: a switch expression must cover every possible value of n, and without default the compiler rejects it.
Expecting a run-time error: the compiler checks coverage before the program runs, whatever value n holds.

How does yield hand a value out of a block branch of a switch expression?
Why does a switch expression over an enum need no default when it lists every constant?

Back to questions Open topic in roadmap →Answer it yourself — Quiz