JuniorTheoryCommon

What does the program print?

package main

import "fmt"

type Temp struct{ C int }

func (t *Temp) String() string { return fmt.Sprintf("%d°C", t.C) }
func main() {
    t := Temp{C: 21}
    fmt.Println(t, &t)
}

{21} 21°C

Expecting 21°C 21°C: String has a pointer receiver, so only *Temp implements fmt.Stringer, and the value t prints as its plain fields.
Expecting the pointer to print as &{21}: &t has the type *Temp, which has the String method, so fmt calls it and prints 21°C.

How would you change the method so that fmt.Println(t) also prints 21°C?
Why can you call t.String() on the variable t, yet t does not implement fmt.Stringer?

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Back to questions

JuniorTheoryCommon

What does the program print?

package main

import "fmt"

type Temp struct{ C int }

func (t *Temp) String() string { return fmt.Sprintf("%d°C", t.C) }
func main() {
    t := Temp{C: 21}
    fmt.Println(t, &t)
}

{21} 21°C

Expecting 21°C 21°C: String has a pointer receiver, so only *Temp implements fmt.Stringer, and the value t prints as its plain fields.
Expecting the pointer to print as &{21}: &t has the type *Temp, which has the String method, so fmt calls it and prints 21°C.

How would you change the method so that fmt.Println(t) also prints 21°C?
Why can you call t.String() on the variable t, yet t does not implement fmt.Stringer?

Back to questions Open topic in roadmap →Answer it yourself — Quiz