JuniorTheoryCommon

What does the program print?

package main

import "fmt"

type Animal struct{}
type Dog struct{ Animal }

func (a Animal) Kind() string { return "pet" }
func (a Animal) Say() string  { return a.Kind() }
func (d Dog) Kind() string    { return "dog" }

func main() { fmt.Println(Dog{}.Kind(), Dog{}.Say()) }

dog pet

Expecting dog dog: Say is a method of Animal, so its a.Kind() calls Animal.Kind; embedding is not inheritance, and Dog's method is never reached.
Expecting pet pet or a compile error: Dog's own Kind shadows the promoted one, so Dog{}.Kind() calls it without any conflict.

How do you still reach an embedded field after an own field shadows it?
If two embedded types promote the same method name, what happens?

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JuniorTheoryCommon

What does the program print?

package main

import "fmt"

type Animal struct{}
type Dog struct{ Animal }

func (a Animal) Kind() string { return "pet" }
func (a Animal) Say() string  { return a.Kind() }
func (d Dog) Kind() string    { return "dog" }

func main() { fmt.Println(Dog{}.Kind(), Dog{}.Say()) }

dog pet

Expecting dog dog: Say is a method of Animal, so its a.Kind() calls Animal.Kind; embedding is not inheritance, and Dog's method is never reached.
Expecting pet pet or a compile error: Dog's own Kind shadows the promoted one, so Dog{}.Kind() calls it without any conflict.

How do you still reach an embedded field after an own field shadows it?
If two embedded types promote the same method name, what happens?

Back to questions Open topic in roadmap →Answer it yourself — Quiz