JuniorTheoryCommon

What does the program print?

package main

import "fmt"

func main() {
    x := 1
    defer fmt.Print(x)
    x++
    defer fmt.Print(x)
    x++
    fmt.Print(x)
}

321

Expecting 333: the arguments of a deferred call are evaluated on the defer line, so the two calls remember 1 and 2, not the final x.
Expecting 312: deferred calls run in reverse order, so the second defer, holding 2, runs before the first one, holding 1.

How would you change the first defer so that it prints the final value of x?
What would the program print if both defer lines came after the last x++?

JuniorTheoryCommon

package main

import "fmt"

func main() {
    x := 1
    defer fmt.Print(x)
    x++
    defer fmt.Print(x)
    x++
    fmt.Print(x)
}

321

Expecting 333: the arguments of a deferred call are evaluated on the defer line, so the two calls remember 1 and 2, not the final x.
Expecting 312: deferred calls run in reverse order, so the second defer, holding 2, runs before the first one, holding 1.

How would you change the first defer so that it prints the final value of x?
What would the program print if both defer lines came after the last x++?