JuniorTheoryCommon

What does the program print?

package main

import "fmt"

func main() {
    n := 0
    next := func() int { n++; return n }
    fmt.Println(next(), next(), next())
}

1 2 3

Expecting 1 1 1: the function literal does not copy n; it uses the variable itself, so each call sees the value the previous call left.
Expecting 0 1 2: n++ is a statement that runs before return n, so the first call already returns 1.

What would a second next2 := func() int { n++; return n } see after these three calls?
How would you give each counter its own n?

JuniorTheoryCommon

package main

import "fmt"

func main() {
    n := 0
    next := func() int { n++; return n }
    fmt.Println(next(), next(), next())
}

1 2 3

Expecting 1 1 1: the function literal does not copy n; it uses the variable itself, so each call sees the value the previous call left.
Expecting 0 1 2: n++ is a statement that runs before return n, so the first call already returns 1.

What would a second next2 := func() int { n++; return n } see after these three calls?
How would you give each counter its own n?