JuniorTheoryCommon

What does the program print?

Console.WriteLine(Get());
int Get()
{
    try
    {
        return 1;
    }
    finally
    {
        Console.Write("B");
    }
}

Expecting 1B: finally runs while Get is still leaving, before the caller gets the value, so B is written first.
Expecting return to leave at once and skip finally: finally runs on every way out of try.

What changes in the output if try throws an exception that the caller catches, instead of returning?
Why can't the finally block hold a return of its own?