JuniorTheoryOccasional

What does the program print?

Count(3);

void Count(int n)
{
    if (n > 0)
    {
        Console.Write(n);
        Count(n - 1);
        Console.Write(n);
    }
}

321123

Expecting 321: the line after the recursive call still runs once that call returns, so each Count prints its n twice.
Expecting 321321: the deepest call finishes first, so the second prints come back in reverse order: 1, 2, 3.

What does the program print if the call is Count(0) instead of Count(3)?
What happens if the condition n > 0 is removed, and can the program recover from it?

JuniorTheoryOccasional

Count(3);

void Count(int n)
{
    if (n > 0)
    {
        Console.Write(n);
        Count(n - 1);
        Console.Write(n);
    }
}

321123

Expecting 321: the line after the recursive call still runs once that call returns, so each Count prints its n twice.
Expecting 321321: the deepest call finishes first, so the second prints come back in reverse order: 1, 2, 3.

What does the program print if the call is Count(0) instead of Count(3)?
What happens if the condition n > 0 is removed, and can the program recover from it?