JuniorTheoryCommon

What does the program print?

C++

#include <iostream>

#define SQUARE(x) x * x

int main() {
    int x = 3;
    std::cout << SQUARE(x + 1) << '\n';
}

Expecting 16: a macro pastes its argument as text, so SQUARE(x + 1) becomes x + 1 * x + 1, not (x + 1) * (x + 1).
Expecting 13: after the substitution the usual precedence applies, so 1 * x is computed first and 3 + 3 + 1 is 7.