JuniorTheoryCommon

What does the program print?

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 5; ++i) {
        if (i % 2 == 0) {
            continue;
        }
        std::cout << i;
    }
}

135

Expecting 1: that is what break does; continue ends only the current iteration, and the loop goes on with the next value of i.
Expecting the loop never to stop: in a for loop, continue still runs the step ++i, so i keeps growing and the loop ends after 5.

What would the program print if continue were replaced with break?
Why can continue make a while loop endless when its counter is incremented at the end of the body?

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JuniorTheoryCommon

What does the program print?

C++

#include <iostream>

int main() {
    for (int i = 1; i <= 5; ++i) {
        if (i % 2 == 0) {
            continue;
        }
        std::cout << i;
    }
}

135

Expecting 1: that is what break does; continue ends only the current iteration, and the loop goes on with the next value of i.
Expecting the loop never to stop: in a for loop, continue still runs the step ++i, so i keeps growing and the loop ends after 5.

What would the program print if continue were replaced with break?
Why can continue make a while loop endless when its counter is incremented at the end of the body?

Back to questions Open topic in roadmap →Answer it yourself — Quiz