JuniorTheoryCommon

What does the program print?

C++

#include <iostream>

void print(int) { std::cout << "int"; }
void print(long) { std::cout << "long"; }
void print(double) { std::cout << "double"; }

int main() {
    print(2.5f);
}

double

Expecting int: float → int is a conversion, float → double a promotion, and a promotion beats a conversion.
Expecting an ambiguity error: a call is ambiguous only when the best candidates tie, and here one is a promotion.

What would print(2.5f) call if only print(int) and print(long) were declared?
Why does print('a') call print(int) here rather than print(long)?

Back to questions Open topic in roadmap →Answer it yourself — Quiz

Back to questions

JuniorTheoryCommon

What does the program print?

C++

#include <iostream>

void print(int) { std::cout << "int"; }
void print(long) { std::cout << "long"; }
void print(double) { std::cout << "double"; }

int main() {
    print(2.5f);
}

double

Expecting int: float → int is a conversion, float → double a promotion, and a promotion beats a conversion.
Expecting an ambiguity error: a call is ambiguous only when the best candidates tie, and here one is a promotion.

What would print(2.5f) call if only print(int) and print(long) were declared?
Why does print('a') call print(int) here rather than print(long)?

Back to questions Open topic in roadmap →Answer it yourself — Quiz